SQLi authorization bypass

Now we know that we can put in any code we want and it's going to be executed on the system. So, let's have another look at the statement, which says select * from accounts where username = username, and password = password, which we put in the Password textbox. We will now see whether we can use that to log in without using a password, and we are going to be doing that with the admin. So, username is going to be admin, and we don't know what password is for admin, so we are going to enter any random password, for example, aaa. In the code that we were previously running, we put and 1=1, now instead of and, we are going to say or 1=1. So, once we inject the command, it is going to let us log in without even knowing the password of admin. Our code is going to look as follows:

select * from accounts where username = 'admin' and password='aaa' or 1=1'

When we log in using the admin Username and paste aaa' or 1=1 in the Password textbox, we can see that we logged in successfully...